Example 5 - Chapter 15 Class 11 Statistics (Term 1)
Last updated at Sept. 6, 2021 by Teachoo
Last updated at Sept. 6, 2021 by Teachoo
Transcript
Example 5 - Chapter 15 Class 11 Statistics - NCERT Find the mean deviation about the median for the following data: xi 3 6 9 12 13 15 21 22 fi 3 4 5 2 4 5 4 3 c.f is Cumulative frequency N = 29 (odd) β΄ Median = ((π + 1)/2)^π‘βterm = ((29 + 1)/2)^π‘β term = (30/2)^π‘β term = 15th term Now, finding mean deviation about median As, 15th term lie in c.f of 21. Median = 30 β128βππ = 29 β128βππ |π₯π βM| = 148 β΄ Mean Deviation = (Ξ£ π_π |π₯_(π )β M|)/π_π = 148/29 = 5.1
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